What is the magnetic moment (spin only) and h | vedclass

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(C) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the iron is in the $+1$ oxidation state $(Fe^+)$.The electronic configuration of $Fe^+$ is $[Ar] 3d

Vedclass · Accepted Answer

$\sqrt{15} \ BM, sp^3d^2$

Vedclass · Answer

(C) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the iron is in the $+1$ oxidation state $(Fe^+)$.The electronic configuration of $Fe^+$ is $[Ar] 3d^6 4s^1$.In this complex,$NO$ acts as $NO^+$,and $H_2O$ is a weak field ligand. The $Fe^+$ ion undergoes $sp^3d^2$ hybridisation.The $3d$ electrons are arranged as $t_{2g}^5 e_g^0$ (or similar distribution),resulting in $3$ unpaired electrons.Magnetic moment $\mu = \sqrt{n(n+2)} \ BM = \sqrt{3(3+2)} = \sqrt{15} \ BM$.Thus,the magnetic moment is $\sqrt{15} \ BM$ and the hybridisation is $sp^3d^2$.

What is the magnetic moment (spin only) and hybridisation of the brown ring complex $[Fe(H_2O)_5NO]SO_4$?

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